Velocity of a particle of mass 2 kg changes from $\overline{v_1}=-2\widehat{i}-2\widehat{j}m/s$ to $\overline{v_2}=(\widehat{i}-\widehat{j})m/s$ after colliding with a smooth plane surface.

The angle made by the plane surface with the positive x-axis is  ${90}^{\circ }+{\tan }^{-1}\left(\frac{1}{3}\right)$

The angle made by the plane surface with the positive x-axis is  ${\tan }^{-1}\left(\frac{1}{3}\right)$

The direction of change in momentum makes an angle ${90}^{\circ }+{\tan }^{-1}\left(\frac{1}{3}\right)$  with the plane surface.

The direction of change in momentum makes an angle ${\tan }^{-1}\left(\frac{1}{3}\right)$ with the positive x-axis.