Velocity of a particle of mass 2 kg changes from $\overrightarrow{v_1}=-2\widehat{i}-2\widehat{j}$ m/s to $\overrightarrow{v_2}=\widehat{i}-\widehat{j}$ m/s after colliding with a smooth plane surface.

The angle made by the plane surface with the positive x-axis is 90º +  ${\tan }^{-1}\left(\frac{1}{3}\right)$

The angle made by the plane surface with the positive x-axis is ${\tan }^{-1}\left(\frac{1}{3}\right)$

The direction of change in momentum makes an angle  ${\tan }^{-1}\left(\frac{1}{3}\right)$ with the positive x-axis

The direction of change in momentum makes an angle 90º +${\tan }^{-1}\left(\frac{1}{3}\right)$ with the plane surface.