Velocity of a particle of mass 2kg changes from $\overrightarrow{v_1}=(-2\widehat{i}-2\widehat{j})$ m/s to $\overrightarrow{v_2}=(\widehat{i}-\widehat{j})$ m/s after colliding with a plane surface.

The angle made by the plane surface with the positive x-axis is ${\tan }^{-1}\left(\frac{1}{3}\right)$

The angle made by the plane surface with the positive x-axis is ${90}^o+{\tan }^{-1}\left(\frac{1}{3}\right)$

The direction of change in momentum makes an angle ${\tan }^{-1}\left(\frac{1}{3}\right)$ with the +ve x-axis

The direction of change in momentum makes an angle ${90}^o+{\tan }^{-1}\left(\frac{1}{3}\right)$ with the plane surface