Velocity of a particle of mass 2kg changes from ${\overrightarrow{\mathrm{v}}}_1=-2\hat{\mathrm{i}}-2\hat{\mathrm{j}} \mathrm{m}/\mathrm{s}$ to ${\overrightarrow{\mathrm{v}}}_2=( \hat{\mathrm{i}}-\hat{\mathrm{j}} ) \mathrm{m}/\mathrm{s}$ after colliding with a plane surface.

The direction of change in momentum makes an angle ${\tan }^{-1}\left(\frac{1}{3}\right)$ with the positive x-axis. 

The angle made by the plane surface with the positive x-axis is ${90}^{\circ }+{\tan }^{-1}\left(\frac{1}{3}\right)$.

The angle made by the plane surface with the positive x-axis is ${\tan }^{-1}\left(\frac{1}{3}\right)$

The direction of change in momentum makes an angle ${90}^{\circ }+{\tan }^{-1}\left(\frac{1}{3}\right)$  with the plane surface.