Q.

Velocity of a particle of mass 2kg changes from v1=2i^2j^ m/s to v2=( i^j^ ) m/s after colliding with a plane surface.

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a

The direction of change in momentum makes an angle tan113 with the positive x-axis. 

b

The angle made by the plane surface with the positive x-axis is 90+tan113.

c

The angle made by the plane surface with the positive x-axis is tan113

d

The direction of change in momentum makes an angle 90+tan113  with the plane surface. 

answer is A, C.

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Detailed Solution

Impulse is change in momentum. Hence, impulse

=2v2v1=2(3i^+j^)=6i^+2j^

Question Image

 

As impulse is in the normal direction of colliding surface

tan θ=13

θ=tan113

α=90+tan113

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