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Velocity of the electron in the 1st Bohr orbit for hydrogen atom

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$2 .18 \times 10^{8} {cms}^{- 1}$

$2 .18 \times 10^{8} {ms}^{- 1}$

$2 .18 \times 10^{16} {cms}^{- 1}$

$36559 \times 10^{8} {cms}^{- 1}$

answer is A.

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Detailed Solution

$V = ? {cms}^{- 1} V = \frac{2 .18 \times 10^{8}}{n} {cms}^{- 1} V = \frac{2 .18 \times 10^{8}}{1} = 2 .18 \times 10^{8} {cms}^{- 1}$

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