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Velocity versus time graph of a ball of mass $50 g$ rolling on a concrete floor is shown in the figure. Find the frictional force of the floor on the ball?

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0.5 N

- 0.5 N

0.25 N

- 0.25 N

answer is B.

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Detailed Solution

Velocity versus time graph of a ball of mass

50 g

rolling on a concrete floor is shown in the figure. The friction force of the floor on the ball is

- 0.5 N

.
First, we find the acceleration

a = \frac{0 - 80}{8} m / s^{2}

= - 10 m / s^{2}

,i.e.in the opposite direction of motion.
Now, Force

F = ma

= \frac{50}{1000} kg \times (- 10)

= - 0.5 N

, i.e.in the opposite direction of motion.

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