AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

Q.

Vijay had some bananas and divided them into two lots A and B. He sold the first lot at the rate of Rs 2 for 3 bananas and the second at the rate of Re 1 per banana and got a total of Rs 400. If he had sold the first lot at the rate of Re 1 per banana, and the second lot at the rate of Rs 4 for 5 bananas, his total collection would have been Rs 460. What is the total number of bananas he had?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

a

350

b

400

c

500

d

450

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Given, Vijay had some bananas and divided them into two lots A and B.
He sold the first lot at the rate of Rs 2 for 3 bananas and the second at the rate of Re 1 per banana and got a total of Rs 400.
If he had sold the first lot at the rate of Re 1 per banana, and the second lot at the rate of Rs 4 for 5 bananas, his total collection would have been Rs 460.
Let the number of bananas that Vijay had in two lots A and B are

x

and

y

respectively. According to the first condition we get,

2 x 3 + 1 y = 400 ⇒ 2 x + 3 y = 1200 .... 1

And, according to the second condition we get,

1 x + 4 y 5 = 460 ⇒ 5 x + 4 y = 2300 .... 2

On multiplying equation (1) by 4 and equation (2) by 3, we get,

8 x + 12 y = 4800

.... 3

And,

15 x + 12 y = 6900

.... 4

On solving equations (3) and (4), we get,

8 x + 12 y = 4800 15 x + 12 y = 6900 − − − ¯ 7 x = 2100 ⇒ x = 300

Now, we substitute

x = 300

in equation (1) to get the value of

y

.

⇒ 2300 + 3 y = 1200 ⇒ 3 y = 600 ⇒ y = 200

Thus, the total number of bananas he had was

200 + 300 = 500

.
Hence, the correct option is 3.

Watch 3-min video & get full concept clarity

courses

No courses found

Related Blogs

Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs

Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

best study material, now at your finger tips!

live classes
progress tracking
24x7 mentored guidance
study plan analysis

download the app

gplay

mentor

Download the App

gplay

personalised 1:1 online tutoring