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Voltmeter shown reads 18 v. The resistance of the voltmeter is

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$\frac{800}{7} Ω$

$75 Ω$

$\frac{900}{7} Ω$

$120 Ω$

answer is D.

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Detailed Solution

$\begin{array}{l} I = \frac{12}{24} = \frac{1}{2} A, I_{1} = \frac{18}{50} A, \\ I_{2} = I - I_{1} = \frac{1}{2} - \frac{18}{50} = \frac{7}{50} A \end{array}$

$R_{V} = \frac{18}{I_{2}} = \frac{18}{7 / 50} = \frac{900}{7} Ω$

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