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Q.

Volume occupied by 28 gm of N2 at 2.46 atm is 10.012 lits. Temperature of the gas is 

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a

300K

b

3000C

c

400K

d

270K

answer is A.

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Detailed Solution

T=2.46×10.0120.0821 = 300K

n = 1 mole

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