Volume occupied by molecules of one mole gas at NTP, each having radius of 10^-8cm is

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10.08 litre

22.4 litre

10.09 mL

22.0 litre

answer is C.

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Detailed Solution

Volume of molecules in one mole
$\begin{array}{l} = 4 \times N \times V = 4 \times N \times \frac{4}{3} {πr}^{3} \\ = 4 \times 6 .023 \times 10^{23} \times \frac{4}{3} \times \frac{22}{7} \times {(10^{- 8})}^{3} = 10 .09 mL \end{array}$

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