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Volume of oxygen (at STP) required for the combustion of 0.5 gram atoms of sulphur is

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11.2 L

5.6 L

22.4 L

2.8 L

answer is A.

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Detailed Solution

$S (s) + O_{2} (g) \to {SO}_{2} (g); 1 gram atom 22.4 L 0.5 gram atoms 11.2 L$

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