Volume of the air that will be expelled from a vessel of $300 {cm}^{3}$ when it is heated from $27^{0} C to 37^{0} C$ at the same pressure will be

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$310 c m^{3}$

$290 c m^{3}$

$10 c m^{3}$

$37 c m^{3}$

answer is C.

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Detailed Solution

$\begin{array}{l} \frac{V_{2}}{V_{1}} = \frac{T_{2}}{T_{1}} \\ ∵ V_{2} = \frac{T_{2}}{T_{1}} V_{1} = \frac{310 K}{300 K} \times 300 {cm}^{3} = 310 {cm}^{3} \end{array}$

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