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Q.

Volume of water that must be added to 10 ml 0.1 M Ba(OH)2 to dilute it to a solution of pH = 12.699 is 

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a

30 ml

b

10 ml

c

25 ml

d

20 ml

answer is B.

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Detailed Solution

pH=1.301[OH]=5×102M

V1N1=V2N2

10(0.1)2=V2(0.05)

VH2O added=(4010)ml=30 ml

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