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Q.

Volume strength of an aqueous solution of $H_{2} O_{2} (d = 1.2085 g / m L)$ is 2.8375. Calculate molality of $H_{2} O_{2}$ solution. (Rounding to Nearest integer)

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Detailed Solution

$2.8375 = M \times 11.35 M = \frac{1}{4}, V = 1 L n = \frac{1}{4},$

Mass of solution $= 12085 g$

$m = \frac{0.25}{(1208.5 - 8.5)} \times 1000 = 0.208 \approx 0.21$

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