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Q.

Volume $V_{1}$ mL of $0.1 M K_{2} {Cr}_{2} O_{7}$ is needed for complete oxidation of $0.678 g N_{2} H_{4}$ in acidic medium. The volume r,f 0.3 M KMnO4 needed for same oxidation in acidic medium will be:

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a

$\frac{2}{5} V_{1}$

b

can not be determined

c

$113 V_{1}$

d

$\frac{5}{2} V_{1}$

answer is A.

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Detailed Solution

The required volume is calculated as,

$V_{1} \times 0.1 \times 6 = 0.3 \times 5 \times V$

Thus, $\frac{2}{5} V_{1}$

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Volume V1 mL of 0.1MK2Cr2O7 is needed for complete oxidation of 0.678 g N2H4 in acidic medium. The volume r,f 0.3 M KMnO4 needed for same oxidation in acidic medium will be: