$\sqrt{\mathrm{v}}$ versus Z graph for characteristic X-rays is as shown in figure. Which match is correct for given graph?

$\sqrt{\gamma }=a(z-b)$

$$\begin{gathered} \mathrm{energy} \mathrm{of} \mathrm{the} \mathrm{photon} \mathrm{due} \mathrm{to} \mathrm{electron} \mathrm{transition} \\ \mathrm{h\nu }=13.6 {\mathrm{Z}}^2\left(\frac{1}{{\mathrm{n}}_1^2}-\frac{1}{{\mathrm{n}}_2^2}\right) \\ \mathrm{for} {\mathrm{k}}_{\mathrm{\alpha }} , {\mathrm{n}}_1=1 \mathrm{and} {\mathrm{n}}_2=2 \mathrm{for} {\mathrm{k}}_{\mathrm{\beta }} , {\mathrm{n}}_1=1 \mathrm{and} {\mathrm{n}}_2=3 \end{gathered}$$

$\mathrm{for} {\mathrm{L}}_{\mathrm{\alpha }}, {\mathrm{n}}_1=2 \mathrm{and} {\mathrm{n}}_2=3; \mathrm{for} {\mathrm{L}}_{\mathrm{\beta }}, {\mathrm{n}}_1=2 \mathrm{and} {\mathrm{n}}_2=4$

$\mathrm{so} \mathrm{maximum} \mathrm{energy} \mathrm{or} \mathrm{frequency} \mathrm{in} {\mathrm{K}}_{{\mathrm{\beta }}_{ }}\mathrm{and} \mathrm{then} {\mathrm{k}}_{\mathrm{\alpha }} \mathrm{then} {\mathrm{L}}_{\mathrm{\beta }} \mathrm{and} \mathrm{then} {\mathrm{L}}_{\mathrm{\alpha }}$