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Water is flowing through a horizontal pipe of variable cross - section. The rate of volume flow is 0.2 lit/sec. The pressure is 30,000 Pa. at a point where the area of cross - section is $5 \times 10^{- 5} m^{2}$ . The pressure at the point where the area of cross-section is $10^{- 4}$ is

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6000 Pa

36000 Pa

24000 Pa

30000 Pa

answer is B.

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Detailed Solution

$A_{1} v_{1} = A_{2} v_{2}$

$A_{1} v_{1} = 0.2 \times 10^{- 3}$

$0.2 \times 10^{- 3} = 5 \times 10^{- 5} v_{1}$

$v_{1} = 4 m s^{- 1}$

$A_{2} v_{2} = 0.2 \times 10^{- 3}$

$10^{- 4} v_{2} = 0.2 \times 10^{- 3} \Rightarrow v_{2} = 2 m / s$

$P_{2} - P_{1} = \frac{ρ}{2} (v_{1}^{2} - v_{2}^{2})$

$P_{2} - P_{1} = \frac{1000}{2} (16 - 4)$

$P_{2} - 30, 000 = 6000$

$P_{2} = 36000 p a$

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