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Water and mercury are filled in two cylindrical vessels up to same height. Both vessels have a hole in the wall near the bottom. The velocity of water and mercury coming out of the holes are V₁ and V₂ respectively.

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$v_{1} = v_{2} / 13.6$

$v_{1} = v_{2}$

$v_{1} = 13.6 v_{2}$

$v_{1} = \sqrt{13.6} v_{2}$

answer is A.

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Detailed Solution

Since the velocity of the liquid going out of the tank is given as velocity v = $\sqrt{2 gh}$ , it is independent of the material's density. As a result, both water and mercury will emerge at the same speed.

Thus $v_{1} = v_{2} .$

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