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Water droplets are coming from an open tap at a particular rate. The spacing between a droplet observed at 4^th second after its fall to the next droplet is 34.3 m. At what rate the droplets are coming from the tap? (Take g = 9.8 m/s²)

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1 drop/7 seconds

3 drops/2 seconds

2 drops/second

1 drop/second

answer is D.

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Detailed Solution

The distance traveled by a freely falling drop is

$Question Image$

Initial velocity is u = 0

In 4 sec, 1st drop will travel.

$h_{1} = \frac{1}{2} \times 9.8 \times 4^{2} = 78.4$

2nd drop would have travel,

$Question Image$

So, the time taken by 2nd drop is

$Question Image$

It means each drop has a time gap of 1 sec.

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Water droplets are coming from an open tap at a particular rate. The spacing between a droplet observed at 4th second after its fall to the next droplet is 34.3 m. At what rate the droplets are coming from the tap? (Take g = 9.8 m/s2)

Detailed Solution

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Water droplets are coming from an open tap at a particular rate. The spacing between a droplet observed at 4^th second after its fall to the next droplet is 34.3 m. At what rate the droplets are coming from the tap? (Take g = 9.8 m/s²)