Water drops are falling from a nozzle of a shower onto the floor, from a height of 9.8m. The drops fall at a regular interval of time. When the first drop strikes the floor, at that instant, the third drop begins to fall. Locate the position of second drop from the nozzle when the first drop strikes the floor.

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

4.18 m

2.94 m

2.45 m

7.35 m

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Using $H= \frac{1}{2} {gt}^{2} \Rightarrow {2H/g=t}^{2} \Rightarrow \frac{9.8 \times 2}{9.8} = t^{2} \Rightarrow t = \sqrt{2} s$

For first drop, t = 0; For second drop, $t=Δt$

For third drop, $t=2Δt$

Let h be the distance travelled by second drop when third drop begins to fall $∴ h= \frac{1}{2} g {(\sqrt{2} - Δ t)}^{2} \Rightarrow 0 = \frac{1}{2} g {(\sqrt{2} - Δ t)}^{2} \Rightarrow Δ t = \frac{1}{\sqrt{2}}$

$∴ h= \frac{1}{2} g {(\sqrt{2} - \frac{1}{\sqrt{2}})}^{2} = \frac{1}{2} \times 9.8 \times \frac{1}{2} = \frac{9.8}{4} = 2.45 m$

Height of second drop from nozzle = 2.45 m

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

How to Join IIT after 10th