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Water drops are falling in regular intervals of time from top of a tower of height 9m. If 4th drop begins to fall when 1st drop reaches the ground, find the positions of 3rd drops from the top of the tower.

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1 m

2 m

3 m

4 m

answer is A.

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Detailed Solution

Let t = time gap between two consecutive drops time of fall of 1st drop = 3t

$9 = \frac{1}{2} g (3 t)^{2} \Rightarrow t^{2} = \frac{1}{5} \sec \to (1)$

time of fall of 3rd drop = t

$h = \frac{1}{2} {gt}^{2} = 2 g \times \frac{1}{5} = 1 m$

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