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Water in a bucket is whirled in a vertical circle with a string attached to it. The water does not fall down even when the bucket is inverted at the top of its path. We conclude that in this position

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$m g = \frac{m v^{2}}{r}$

mg is greater than $\frac{{mv}^{2}}{r}$

mg is not greater than $\frac{m v^{2}}{r}$

none of these

answer is C.

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Detailed Solution

$\frac{m v^{2}}{r} > m g$

At highest point mg = $\frac{m v^{2}}{r} - N$

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