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Water in a canal 30dm wide, 12dm deep is flowing with the velocity l20km/hr. How much area will it irrigate in 30 minutes if 8cm of standing water is required?

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a

225000

m^{2}

b

256000

m^{2}

c

345000

m^{2}

d

567000

m^{2}

answer is A.

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Detailed Solution

Concept- We are given the velocity of water and time using which we can find the length of the canal. Now using the length, width and depth we can find the volume and out of that 8cm is standing so we need to find the remaining area.
We have,
Width of the canal

= 30 dm = 300 cm = 3 m

Depth of the canal

= 12 dm = 120 cm = 1.2 m

water is flowing at a velocity of 10km/hr.
Therefore length of the water column formed in

\frac{1}{2} hour = 5 km = 5000 m

volume of the water flowing in

\frac{1}{2}

hour
= Volume of the cuboid of length is 5000m, width is 3m and depth is 1.2m
Volume of the water following in

\frac{1}{2}

hour
=5000×3×1.2

m^{3}

=18000

m^{3}

Suppose

x m^{2}

area is irrigated in

\frac{1}{2}

hour. Then

x \times \frac{8}{100} = 18000

x = 225000 m^{2}

Hence, the correct option is 1.

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