Water in a clean aquarium forms a meniscus, as shown in the figure.
T = surface tension of liquid
h = difference of height between centre and the edge
$ρ$ = density of liquid.

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$h \propto {(\frac{T}{ρ})}^{\frac{3}{2}}$

$h \propto {(\frac{T}{ρ})}^{\frac{1}{2}}$

$h \propto {(\frac{T}{ρ})}^{2}$

$h \propto \frac{T}{ρ}$

answer is B.

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Detailed Solution

In the FBD only horizontal forces are shown.
Question Image
$l =$ length of side wall of aquarium
In equation
$F_{1} - F_{2} - F_{3} = 0 h = \sqrt{\frac{2 T}{ρ g}}$

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