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Water is drawn from a well in a 5 kg drum of capacity 55 L by two ropes connected to the top of the drum. The linear mass density of each rope is 0.5 kg m^-1. The work done in lifting water to the ground from the surface of water in the well 20 m below is $[g = 10 {ms}^{- 2}]$

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$1 .5 \times 10^{4} J$

$1 .4 \times 10^{4} J$

$9 .8 \times 10 \times 6 J$

$18 J$

answer is A.

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Detailed Solution

Mass of water $= 55 \times 10^{- 3} \times 10^{3} = 55 kg$ $(1 L = 10^{- 3} m^{3})$

Work done in lifting water and drum is

$60 \times 10 \times 20 J = 12000 J$

Total mass of ropes $= 40 \times 0 .5 kg = 20 kg$

Work done in the case of ropes is

$20 \times 10 \times 10 = 2000 J$

Total work done = 14000 J

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