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Water is falling on the blades of a turbine at the rate of $8 \times 1 0^{2} kg$ per minute, height of fall is $50 m$ . The power given to the turbine is (Take $g = 10 m / s^{2}$ )

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6.67 kW

667 W

66.7 kW

None of these

answer is A.

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Detailed Solution

Water is falling on the blades of a turbine at the rate of

8 \times 1 0^{2} kg

per minute, height of fall is

50 m

. The power given to turbine is

6.67 kW .

Given:
height,

h = 50 m

gravitational acceleration

g = 10 m / s^{2}

mass,

m = 8 \times 10^{2} kg

time,

t = 1 \min = 60 s

∴ P = \frac{W}{t}

\Rightarrow = \frac{mgh}{t}

[

W = Force \times displacement

]

\Rightarrow = \frac{8 \times 10^{2} \times 10 \times 50}{60}

\Rightarrow = 6.67 \times 10^{3} W

P = 6.67 kW

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