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Water is filled in a flask up to a height of 20cm. The bottom of the flask is circular with radius 10cm. If the atmospheric pressure is $1 .0 1 \times 1 0^{5} pa$ . The force exerted by water on the bottom is

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2.3 \times 1 0^{5} N

2330N

3 \times 1 0^{4} N

3230N

answer is B.

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Detailed Solution

Given that a flask is filled with water

h = 20 cm = 0.2 m , $P_{0} = 1.01 \times 10^{5} Pa$

We can have pressure P at the bottom as

$P = P_{atm} + h ρ g$

$= 1.01 \times 10^{5} + 0.2 \times 1000 \times 10$

$= 1.03 \times 10^{5}$

$F = P \times A$

$= 1.03 \times 10^{5} \times 3.14 \times 10^{- 2}$

$= 3.23 \times 10^{3}$

$= 3230 N$

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