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Water is filled into a container with hexagonal cross section of side 6 cm. If the surface tension of water is 0.075Nm^-1 then the surface energy of water will be

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8.5 \times 10^{- 4} J

2.8 \times 10^{- 4} J

6.4 \times 10^{- 4} J

7 \times 10^{- 4} J

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detailed solution

Correct option is D

The surface energy of water surface = surface area $\times$ T

Thus the surface energy of water's surface =

$= (6 \times \frac{\sqrt{3}}{4} a^{2}) T$

$= (6 \times \frac{\sqrt{3}}{4} \times {(6 \times 10^{- 2})}^{2}) \times 0.07 T = 7 \times 10^{- 4} J$

Hence the correct answer $7 \times 10^{- 4} J .$

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Water is filled into a container with hexagonal cross section of side 6 cm. If the surface tension of water is 0.075Nm-1 then the surface energy of water will be

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Water is filled into a container with hexagonal cross section of side 6 cm. If the surface tension of water is 0.075Nm^-1 then the surface energy of water will be