Water is flowing at a speed of 1.5ms^–1 through a horizontal tube of cross-sectional area 10^–2m² and you are trying to stop the flow by your palm. Assuming that the water stops immediately after hitting the palm, the minimum force that you must exert should be (density of water = 10³kgm^–3)

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33.7 N

15 N

22.5 N

45 N

answer is B.

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Detailed Solution

Force exerted will be due to the rate of change of momentum. The final momentum after hitting is zero.

Therefore,
$F = m \frac{dv}{dt}$
For t=1s, we have
$F = ρV \frac{dv}{dt} = (10^{3}) (10^{- 2}) \times 1.5 \times 1.5 = 22.5 N$

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