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Q.

Water is flowing at the rate of 2.52 kmph   through a cylindrical pipe into a cylindrical tank, the radius of whose base is 40 cm  . If the increase in the level of water in the tank, in half an hour is 3.15 m  , find the internal diameter of the pipe.


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a

4 cm

b

5 cm

c

9 cm

d

1 cm 

answer is A.

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Detailed Solution

Given that, flow rate of water is 2.52kmph, base radius of cylindrical tank is 50cm.
Water level increase is 3.15m in half an hour.
Volume of cylinder, V=π r 2 h  , where r is radius, h is height.
Let the internal diameter of the pipe be r   m and water flows in 1hour=2.52km   .
The water flows in 1 2 hour   = 2.52 2   1.26km   1260 m  
The volume of water flows in 1 2  hour =π r 2 h   π r 2 ×1260  
The volume of the water in a cylindrical tank =π× 40 100 2 ×3.15  
Volume of water flow is equal to Volume of increased water,
π r 2 ×1260=π 2 5 2 ×3.15  
1260 r 2 = 2 5 × 2 5 ×3.15  
r 2 = 4 25 × 315 100 × 1 1260 = 1 2500  
r= 1 50 m  
r=2 cm   The diameter of a pipe.
D=2R  
D=2×2cm  
D=4 cm  
Thus, the internal diameter of pipe is 4cm.
Therefore, option (1) is correct.
 
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Water is flowing at the rate of 2.52 kmph   through a cylindrical pipe into a cylindrical tank, the radius of whose base is 40 cm  . If the increase in the level of water in the tank, in half an hour is 3.15 m  , find the internal diameter of the pipe.