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Q.

Water is the change in entropy when 2.5 mole of water is heated from 27° C to 87° C? Assume that the heat capacity is constant.

Cp.m H2O=4.2J/gK,ln(1.2)=0.18

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a

1.89 J/K

b

34.46 J/K

c

16.6 J/K

d

9 J/K

answer is C.

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Detailed Solution

 Solution η=2.5 mole 

T1=27C=300 K

T2=87C=360K

Cpm(ne)=4.2 J/g-K

t2/t1=360/300=0.18

Δs=nCptmT2t1

Hence,Cp=molarmars × cpm

=18×4.2

ΔS=2.5×4.2×18×ln(0.18)=34.025J/K

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