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Water raises to a height of 10cm in a capillary tube and mercury falls to a depth of 3.5cm in the same capillary tube. If the density of mercury is 13.6 gm/c.c and its angle of contact is 135° and density of water is 1 gm/c.c and its angle of contact is 0°, then the ratio of surface tensions of two liquids is (cos 135° = 0.7)

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An Intiative by Sri Chaitanya

1:14

5:34

1:5

5:27

answer is B.

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Detailed Solution

$T = \frac{rhdg}{2}$

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