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Water rises in a capillary up to a height of 4 cm. If it is tilted to $30^{0}$ from the vertical, then the length of water column in it will be

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$\frac{8}{\sqrt{3}}$ cm

$8 \sqrt{3} c m$

4 cm

2 cm

answer is A.

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Detailed Solution

$\cos θ = \frac{h}{l} \Rightarrow l = \frac{h}{\cos 30} = \frac{4}{\sqrt{3} / 2} = \frac{8}{\sqrt{3} c m}$

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