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Q.

Water saturated with air (20% O2 and 80% N2) at 1 atm and 298 K contains 8.9×10−3gL−1 dissolved oxygen. Its solubility under 25 atm pressure of O2 will be

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a

1.834×10−2gL−1

b

1.1125 gL−1

c

8.9×10−3gL−1

d

1.5642 gL−1

answer is B.

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Detailed Solution

Since p=kHc,

we have 0.20 atm =kH8.9×10−3gL−1  and 25atm=kHc

Hence, c=8.9×10−3gL−1(25atm)/0.20atm=1.1125 gL−1

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