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Water was taken in four beakers labeled as I to IV. In these beakers, the following substances were added.
Beaker I : Common salt, Beaker II : Alum

Beaker III : Potassium nitrate

Beaker IV : A few drops of Barium chloride and a few drops of dil. $H_{2} S O_{4}$

After some time, the contents of the beakers were filtered. The contents of which beaker will leave residue on the filter paper ?

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Beaker IV

Beaker I

Beaker III

Beaker II

answer is D.

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Detailed Solution

Among the four beakers, from the First three beakers the compounds are soluble in water but in beaker IV there is formation of precipitate

{BaSO}_{4}

$BaC l_{2 (a q)} + H_{2} {SO}_{4(aq)} \to \underset{white ppt}{{BaSO}_{4}} + 2 HC l_{(a q)}$ .

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