Wave length of electromagnetic radiation having a frequency of $6\times {10}^{14} \mathrm{Hz}$is

$$\begin{gathered} \mathrm{\lambda }=\frac{\mathrm{C}}{\mathrm{\nu }}; \\ \mathrm{\lambda }=\frac{3\times {10}^8 \mathrm{m}/\mathrm{s}}{6\times {10}^{14} {\mathrm{s}}^{-1}}; \\ \mathrm{\lambda }=0.5\times {10}^{-6}\mathrm{m}; \\ 1{\mathrm{A}}^0={10}^{-10}\mathrm{m}; \\ 10{\mathrm{A}}^0=1 \mathrm{nm}={10}^{-9}\mathrm{m}=1\mathrm{m\mu }; \\ 1 \mathrm{pm}={10}^{-12}\mathrm{m}; \\ \therefore \mathrm{\lambda }=500000 \mathrm{pm}=5000{\mathrm{A}}^0=500 \mathrm{nm}=500 \mathrm{m\mu }; \end{gathered}$$