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Q.

Wavelength of an electron is 5Aº. Velocity of the electron is

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a

1.45 × 108 cm/s

b

1.6 × 10–8cm/s

c

3.2 × 10–27cm/s

d

3.2 × 1027cm/s

answer is A.

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Detailed Solution

λ=hmv

me = 9.1 × 10-28 g

λ = 5 × 10-8 cm

v=hm×1λ

v=6.625×10-27erg·sec9.1×10-28×15×10-8

ve = 1.45 × 108 cm

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