Wavelength of electron waves in two Bohr orbits is in ratio 3: 5. The ratio of kinetic energy of electron is 25 : x, hence x is :

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answer is 9.

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Detailed Solution

$\frac{λ_{1}}{λ_{2}} = \frac{n_{1}}{n_{2}} = \frac{3}{5};$

$\frac{{KE}_{1}}{{KE}_{2}} = \frac{n_{2}^{2}}{n_{1}^{2}} \frac{n_{2}^{2}}{n_{1}^{2}} = \frac{5^{2}}{3^{2}} \frac{n_{2}^{2}}{n_{1}^{2}} = \frac{25}{9}$

If the ratio of kinetic energy of electron is 25 : x

Then, the value of x is 9.

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