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Wavelength of high energy transition of H-atoms is 91.2nm. Calculate the corresponding wavelength of ${Li}^{+ 2}$ .

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$10.13 n m$

$22.8 A °$

$22.8 n m$

$10.13 A °$

answer is A.

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Detailed Solution

For H-atom $\frac{1}{λ_{H}} = R_{H} [\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}]$

$λ_{L i^{+ 2}} = λ_{H} \times \frac{1}{Z^{2}} = 91.2 \times \frac{1}{3^{2}} = \frac{91.2}{9} m m = 10.13 n m$

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