Wavelength of the Balmer $H_{α}$ line is $6565 " Å "$ Calculate the wavelength $(in " Å ")$ of $H_{β}$ line of same hydrogen like atom.

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answer is 4863.

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Detailed Solution

Required wavelength;

$\begin{aligned} \frac{1}{λ_{α}} = R_{H} [\frac{1}{2^{2}} - \frac{1}{3^{2}}] \\ \frac{1}{λ_{β}} = R_{H} [\frac{1}{2^{2}} - \frac{1}{4^{2}}] \end{aligned}$

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