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Wax is coated on the inner wall of a capillary tube and the tube is then dipped in water. Then, compared to the unwaxed capillary, the angle of contact $θ$ and the height h up to which water rises change. These changes are:

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$θ$ decreases and h increases

$θ$ increases and h also increases

$θ$ increases and h decreases

$θ$ decreases and h also decreases

answer is C.

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Detailed Solution

Due to waxing, adhesion decreases so, contact angle increases i.e $θ ↑↑$ .

$∵ h = \frac{2 Tcos θ}{rρg}$
$hence, h decreases .$

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