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Q.

We can say that the energy of a photon of frequency v is given by E = hv, where h is Planck's constant. The momentum of a photon is $p = h / λ$ , where $λ$ is the wavelength of photon. Then we may conclude that velocity of light is equal to:

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a

Ep

b

(E / p)^1/2

c

E / p

d

(E / p)²

answer is B.

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Detailed Solution

$\begin{array}{l} p = mu = \frac{h}{λ} and E = \frac{hc}{λ} \\ ∴ E = \frac{c}{λ} \cdot p \cdot λ = c \cdot p \end{array}$

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We can say that the energy of a photon of frequency v is given by E = hv, where h is Planck's constant. The momentum of a photon is p=h/λ, where λ is the wavelength of photon. Then we may conclude that velocity of light is equal to: