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We have two lenses, a convex lens with a focal length $20 cm$ and a concave lens with a focal length $25 cm$ . What are the values of their powers?

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P 1 = + 2 D,

and

P 2 = + 3 D

P 1 = + 5.0 D

and

P 2 = - 4.0 D

P 1 = - 4.0 D

and

P 2 = 7.0 D

None of the above

answer is B.

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Detailed Solution

We have two lenses, a convex lens with a focal length

20 cm

and a concave lens with a focal length

25 cm

. Power of the Lens

P = + 5.0 D

and

P 2 = - 4.0 D

The focal length of the convex lens,

f 1 = + 20 cm

= 0.20 m

.
Formula,

P 1 = \frac{1}{f 1 (in m)}

⇒

P 1 = \frac{1}{0.20}

⇒

P 1 = + 5.0 D

Again, Focal length of concave lens,

F 2 = - 25 cm

= - 0.25 m

.
⇒

P 2 = \frac{1}{f 2 (in m)}

\Rightarrow P 2 = - \frac{1}{0.25}

⇒

P 2 = - 4.0 D

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