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Q.

Weight of 20% pure limestone which liberates 4.4 grams of carbon dioxide on heating is

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a

25 g

b

50 g

c

2 g

d

40 g

answer is B.

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Detailed Solution

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CaCO3(s) →CaO(s) + CO2(g)
100g                              44 g
10g                                4.4 g
weight of 100% pure limestone required = 10g
weight of 20% pure limestone required   = 10×10020=50 g ;

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