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Weight of 40% Pure limestone which produces 2.24 lit of ${CO}_{2}$ at STP is

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25g

16g

answer is C.

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Detailed Solution

${CaCO}_{3} \to CaO + {CO}_{2}$
100g 22.4l
10g 2.24l
Weight of 100% Pure ${CaCO}_{3}$ required = 10g
Weight of 40% Pure ${CaCO}_{3}$ required = $\frac{100}{40} \times 10 = 25 g$

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