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Q.

Weight of 50% pure $C a C O_{3}$ required to liberate 22.4 litres of $C O_{2}$ at STP is

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a

100g

b

200g

c

50g

d

400g

answer is C.

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Detailed Solution

$C a C O_{3} (s) \to C a O (s) + C O_{2} (g)$

$100 g C a C O_{3} \to 22.4 l (S T P)$

$∵$ the purity is only 50%

$W_{C a C O_{3}} = \frac{1000}{50} \times 100 = 200 g$

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Weight of 50% pure CaCO3 required to liberate 22.4 litres of CO2 at STP is