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Q.

Weight of 50% pure ${KClO}_{3}$ required to produce three moles of oxygen on thermal decomposition is (Molar mass of ${KClO}_{3} = 122.5 g)$

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a

61.25 g

b

122.5 g

c

490 g

d

980 g

answer is D.

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Detailed Solution

$2 {KClO}_{3} \to 2 KCl + 3 O_{2}$

$2 \times 122.5 g 3 moles$

$∵ the purity is 50 %$

$W_{{KClO}_{3}} = 245 \times \frac{100}{50} = 490 g$

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