Weight of copper (atomic mass 63.5) deposited when 2 Faradays of electricity is passed through cupric salt solution is

$C{u}^{2+\hspace{0.17em}}+\hspace{0.17em}2e^{-}\to Cu$

to deposit 1 mol of Cu (63.5 g ) , required 2 mol of electron.

1 mol electron = 1Farday. 

Hence, 2 F electricity deposits 63.5 g of Copper.