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Weight of glucose which contains one gram atom of oxygen is

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90 g

10 g

30 g

50 g

answer is C.

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Detailed Solution

$C_{6} H_{12} O_{6} = 180 g (molarmass)$

180 g contain - 6 moles of oxygen atoms ?

? - 1 mole of oxygen atoms

$W_{glucose} = \frac{180}{6} = 30 g$

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