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Weight of one mole of unit cells of NaCl crystals is ––––––––––––

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58.5 gm

58.5amu

234 gm

234 amu

answer is C.

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Detailed Solution

Number of formula units/unit cell of NaCl = 4

Explanation:- NaCl has fcc arrangement Cl¯ ions occupy corners and face centres

Effective number of Cl¯ ions/unitcel

large =left( 8times frac{1}{8} right)+6left( frac{1}{2} right)=4

Na⁺ ions occupy edge centres and body centre

Effective number of Na⁺ ions/unit cell

large =12left( frac{1}{4} right)+1left( 1 right)=4

Thus number of NaCl units/unit cell = 4Na⁺4Cl¯

= 4NaCl units

We know,

58.5 g of NaCl contian "N_A" NaCl units

58.5 g of NaCl contain

unit cells

"X" g of NaCl conain N_A unit cells (1 mole of unit cells)

large X=frac{58.5times {{N}_{A}}}{left( frac{{{N}_{A}}}{4} right)}g

= 234 g

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